Private Sub OK1_Click()
Static count As Integer
count = count + 1
If Len(Nz(Me!UserName)) = 0 And Len(Nz(Me!UserPassword)) = 0 And count <= 3 Then
MsgBox "用户名、密码为空!请输入" + Chr(13) + Chr(13) + " 您还有 " & 3 - count & "次机会", vbCritical, "提示"
Me!UserName.SetFocus
Elself Len(Nz(Me!UserName)) = 0 And count <= 3
MsgBox "用户名为空!请输入" + Chr(13) + Chr(13) + " 您还有 " & 3 - count & " 次机会", vbCritical, "提示"
Me!UserName.SetFocus
ElseIf Len(Nz(Me!UserPassword)) = 0 And count <= 3 Then
MsgBox "密码不能为空!请输入" + Chr(13) + Chr(13) + "您还有 " & 3 - count & " 次机会", vbCritical, "提示"
Me!UserPassword.SetFocus
Else
If Me!UserName = "wz123" Then
If UCase(Me!UserPassword) = "ABC" Then
MsgBox "欢迎使用!", vbInformation, "成功"
count = 0
DoCmd.Close
DoCmd.OpenForm "学员窗口"
Else
MsgBox "密码有误!" + Chr(13) + Chr(13) + "您还有 " & 3 - count & " 次机会 ", vbCritical, "警告"
End If
Else
MsgBox "用户名有误!" + Chr(13) + Chr(13) + Chr(13) + "您还有 " & 3 - count & "次机会", vbCritical, "警告"
End If
End If
If count >= 3 Then
MsgBox " 请确认用户名和密码后再登录 ", vbCritical, "警告"
DoCmd.Close
End If
End Sub
请问登录窗口这样设计为什么有错误?