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如何将SQL查询语句直接写入VBA代码,而不用建立辅助的查询表

Jack  发表于:2015-12-30 10:52:36  
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如何将SQL查询语句直接写入VBA代码,而不用建立辅助的查询表???

查询:QryPbZone

QryPbZone如何将此SQL查询语句直接写入VBA代码,无需借用此查询表

SELECT DISTINCT Left([PlID],5) AS 区域ID,

DLookUp("PzName","PbZone","PzID='" & Right([区域ID],3) & "'") AS 区域名称, 

DLookUp("PtID","PbType","Right([PtID],2)='" & Left([区域ID],2) & "'") AS 属性ID, 

DLookUp("PtName","PbType","Right([PtID],2)='" & Left([区域ID],2) & "'") AS 属类名称

FROM PjList
WHERE (((Left([PlID],5))<>"0"))
ORDER BY Left([PlID],5);


Private Sub TreeLoad()
Dim nodeindex As Node

Dim strSQL as String
Dim Rec As New ADODB.Recordset
Dim i As Integer
'设置爷
Set nodeindex = TVInput.Nodes.Add(, , "爷", "项目列表(List)", "K1", "K2")
nodeindex.Sorted = False
'设置父
   Rec.Open "SELECT * FROM PbType ORDER BY PtID;", CurrentProject.Connection, adOpenKeyset, adLockOptimistic, adCmdTableDirect
    For i = 0 To Rec.RecordCount - 1
     Set nodeindex = TVInput.Nodes.Add("爷", tvwChild, "父" & Rec.Fields("PtID"), Rec.Fields("PtName"), "K3", "K4")
     nodeindex.Sorted = False
     Rec.MoveNext
    Next i
   Rec.Close
'设置子
'* ---------------------------

strSQL="查询QryPbZone的SQL语句":如何利用字符串变量strSQL,将SQL语句直接写入VBA代码,让Rec.Open"strSQL"
   Rec.Open "QryPbZone", CurrentProject.Connection, adOpenKeyset, adLockOptimistic, adCmdTableDirect
    For i = 0 To Rec.RecordCount - 1
        Set nodeindex = TVInput.Nodes.Add("父" & Rec.Fields("属性ID"), tvwChild, "子" & Rec.Fields("区域ID"), Rec.Fields("区域名称"), "K5", "K6")
        nodeindex.Sorted = False
        Rec.MoveNext
    Next
    Rec.Close
'设置孙
'* ---------------------------
   Rec.Open "QryPjList", CurrentProject.Connection, adOpenKeyset, adLockOptimistic, adCmdTableDirect
    For i = 0 To Rec.RecordCount - 1
        Set nodeindex = TVInput.Nodes.Add("子" & Left(Rec.Fields("PlID"), 5), tvwChild, "孙" & Rec.Fields("PlID"), Rec.Fields("PlName"), "K7", "K8")
        nodeindex.Sorted = False
        Rec.MoveNext
    Next
    Rec.Close
End Sub




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Jack 发表于:2015-12-30 14:18:58
SQL语句VBA代码报错提示

煮江品茶 发表于:2016-01-02 10:04:07

双引号错误嘛。

试试:
select DISTINCT Left(a.[PlID],5) AS 区域ID,b.PzName AS 区域名称,c.PtID AS 属性ID,c.PtName as 属类名称
from PjList as a 
inner join PbZone as b on b.PzID=mid(a.PlID,2,3)
inner join PbType as c on Right(c.PtID,2)=left(a.PlID,2)

参见:http://www.accessoft.com/article-show.asp?id=10118




Jack 发表于:2016-01-08 10:00:26
煮江品茶 老师, 我按照您上述代码去写,结果错位!!!请指教指正

Jack 发表于:2016-01-08 10:20:47

a单独与b链接:ok

select DISTINCT Left(a.[PlID],5) AS 区域ID,b.PzName AS 区域名称
from PjList as a 
inner join PbZone as b on b.PzID=MID(a.[plID],3,3)
a单独与c链接:ok

select DISTINCT Left(a.[PlID],5) AS 区域ID,c.PtID AS 属性ID,c.PtName as 属类名称
from PjList as a 
inner join PbType as c on Right(c.PtID,2)=left(a.PlID,2)
然而,a同时与b和c链接,就不对了:

select DISTINCT Left(a.[PlID],5) AS 区域ID,b.PzName AS 区域名称,c.PtID AS 属性ID,c.PtName as 属类名称
from PjList as a 
inner join PbZone as b on b.PzID=MID(a.[plID],3,3)
inner join PbType as c on Right(c.PtID,2)=left(a.PlID,2)
请指教????



Jack 发表于:2016-01-08 10:33:20

最终正确答案:

select DISTINCT Left(a.PlID,5) AS 区域ID,b.PzName AS 区域名称,c.PtID AS 属性ID,c.PtName as 属类名称

from (PjList as a inner join PbZone as b on b.PzID=MID(a.plID,3,3))

inner join PbType as c on Right(c.PtID,2)=left(a.PlID,2)


参阅资料:

1、SQL语句(三)INNER JOIN ... ON用法http://http://www.accessoft.com/article-show.asp?id=6592

2、sql语句(二)inner joinhttp://http://www.accessoft.com/article-show.asp?id=6585



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