分解特殊字符:“123456789012345678-80/95”
时 间:2017-08-03 14:56:22
作 者:易勋 ID:35404 城市:上海
摘 要:分解特殊字符:“123456789012345678-80/95”
123456789012345678
123456789012345679
123456789012345680
123456789012345695
正 文:
函数:
Public Function SplitInCo(strChar As String) As String
Dim strInvoiceNumber As String
Dim strInvoiceCode As String
Dim intS As Integer
Dim intLen As Integer
Dim inti As Integer
Dim strInv As String
Dim strTemp As String
Dim strType As String
Dim arrInvoice() As String
Dim intArr As Integer
Dim strInvoice As String
Dim lngInv As Long
Dim strFormat As String
intLen = Len(strChar)
Select Case intLen
Case Is < 18
SplitInCo = ""
Case Is = 18
If Not strChar Like "*-*" And Not strChar Like "/" Then
SplitInCo = strChar
strInvoiceCode = Left(strChar, 10)
strInvoiceNumber = Right(strChar, 8)
Else
SplitInCo = ""
End If
Case 19
SplitInCo = ""
Case Is > 19
If Mid(strChar, 19, 1) = "-" or Mid(strChar, 19, 1) = "/" Then
strInvoice = Left(strChar, 18)
intArr = 0
inti = 0
strType = Mid(strChar, 19, 1)
For intS = 20 To intLen
strTemp = Mid(strChar, intS, 1)
strInv = strInv & strTemp
If strTemp = "-" or strTemp = "/" or intS = intLen Then
If intS <> intLen Then
strInv = Left(strInv, Len(strInv) - 1)
End If
Select Case strType
Case "-"
For inti = 1 To Len(strInv)
strFormat = strFormat & "0"
Next
If Val(Right(Split(strInvoice, "|")(intArr), Len(strInv))) < Val(strInv) Then
For lngInv = Val(Right(Split(strInvoice, "|")(intArr), Len(strInv))) + 1 To Val(strInv)
strInvoice = strInvoice & "|" & Left((Split(strInvoice, "|")(intArr)), 18 - Len(strInv)) & Format(lngInv, strFormat)
intArr = intArr + 1
Next
End If
strFormat = ""
Case "/"
If Len(strInv) <= 8 Then
strInvoice = strInvoice & "|" & Left((Split(strInvoice, "|")(intArr)), 18 - Len(strInv)) & strInv
intArr = intArr + 1
Else
strInvoice = strInvoice & "|" & strInv
intArr = intArr + 1
End If
' Case Else
' strInvoice = strInvoice & "|Error"
End Select
strInv = ""
strType = strTemp
End If
Next
SplitInCo = intArr + 1
SplitInCo = strInvoice
Else
SplitInCo = ""
End If
End Select
End Function
用法:
SplitInCo("123456789012345678-80/95")
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